[BOJ 5430] Integer list

아래 문제에서 error를 출력할때 continue를 입력했을경우, break 대신에 error가 무기한 출력이되는 문제가 발생한다.
BAPC 2012 문제의 테스트 케이스를 분석해보고 나서야 깨달았다............. 주의해야 겠다

	#include <iostream>
	#include <vector>
	#include <string>
	#include <deque>
	using namespace std;
	int main()
	{
	deque<int> deq;
	int T;
	cin >> T;
	string op;
	int ary_size, num;
	for (int i = 0; i < T; i++) {
	cin >> op;
	cin >> ary_size;
	char ch;
	bool reverse = false;
	cin >> ch;
	deq.clear();
	for (int j = 0; j < ary_size; j++) {
	cin >> num;
	cin >> ch;
	deq.push_back(num);
	}
	if (ary_size == 0)
	cin >> ch;
	bool print = true;
	for (int j = 0; j < op.size(); j++) {
	if (op[j] == 'R')
	{
	reverse = !reverse;
	}
	else if (op[j] == 'D') {
	if (deq.empty())
	{
	cout << "error" << endl;
	print = false;
	break;
	}
	if (reverse)
	deq.pop_back();
	else
	deq.pop_front();
	}
	}
	if (print == false)
	continue;
	cout << "[";
	if (reverse) {
	for (int i = 0; i < deq.size()/2; i++) {
	int temp = deq[i];
	deq[i] = deq[deq.size() - i - 1];
	deq[deq.size() - i - 1] = temp;
	}
	}
	for (int j = 0; j < deq.size(); j++) {
	if (j == deq.size() - 1) {
	cout << deq[j];
	}
	else
	cout << deq[j] << ",";
	}
	cout << "]" << endl;
	}
	}

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